How much current will be drawn by an incandescent bulb connected to a 115-volt circuit if its resistance is 264.5 ohms?

How much current will be drawn by an incandescent bulb connected to a 115-volt circuit if its resistance is 264.5 ohms?

• A. 0.45 amps
• B. 0.43 amps
• C. 0.42 amps
• D. 2.3 amps

Answer: (B)

To find the current drawn by an incandescent bulb connected to a circuit, you can use Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R). This can be expressed mathematically as: \[ I = \frac{V}{R} \] In this scenario, the voltage (V) is 115 volts, and the resistance (R) is 264.5 ohms. Plugging these values into the formula gives: \[ I = \frac{115 \text{ volts}}{264.5 \text{ ohms}} \] When you perform the calculation: \[ I = 0.434 \text{ amps} \] Rounding this to two decimal places, the current drawn is approximately 0.43 amps. This aligns with the provided answer, making it the most accurate choice. The calculation is key here; using the proper formula and substituting in the correct values confirms that the incandescent bulb in this circuit will draw about 0.43 amps, hence validating the correctness of the answer.

To find the current drawn by an incandescent bulb connected to a circuit, you can use Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R). This can be expressed mathematically as:

[ I = \frac{V}{R} ]

In this scenario, the voltage (V) is 115 volts, and the resistance (R) is 264.5 ohms. Plugging these values into the formula gives:

[ I = \frac{115 \text{ volts}}{264.5 \text{ ohms}} ]

When you perform the calculation:

[ I = 0.434 \text{ amps} ]

Rounding this to two decimal places, the current drawn is approximately 0.43 amps. This aligns with the provided answer, making it the most accurate choice.

The calculation is key here; using the proper formula and substituting in the correct values confirms that the incandescent bulb in this circuit will draw about 0.43 amps, hence validating the correctness of the answer.